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An artificial satellite is revolving in ...

An artificial satellite is revolving in a circular orbit at a height of 1200 km above the surface of the earth. If the radius of the earth is 6400 km, mass is `6 xx 10^(24) kg` find the orbital velocity
`(G = 6.67 xx 10^(-11)Nm^(2)//kg^(2))`

Text Solution

Verified by Experts

`V_(0) = sqrt((GM)/(R+H)) = sqrt(((6.67 xx 10^(-11))(6 xx 10^(24)))/((6400 xx 10^(3)) + (1200 xx 10^(3))))`
`= sqrt((6.68 xx 10^(-11) xx 6 xx 10^(24))/(7600 xx 10^(3))) = 7.26 km//s`
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