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A bomb at rest at the summit of a cliff ...

A bomb at rest at the summit of a cliff breaks into two equal fragments. One of the fragments attains a horizontal velocity of `20sqrt(3) ms^(-1)`. The horizontal distance between the two fragments, when their displacement vectors is inclined at `60^@` relative to each other is `(g = 10ms^(-2))`

A

`40sqrt3 m`

B

`80sqrt3m`

C

`120 sqrt3m`

D

`480 sqrt3m`

Text Solution

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The correct Answer is:
D
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