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A body is projected vertically up with v...

A body is projected vertically up with velocity u from a tower. It reaches the ground with velocity nu. The height of the tower is `H=u^2/(2g)(n^2-1)`

Text Solution

Verified by Experts

`v^(2)-u^(2)=2as`
Here `u=u,v=n u,a=-g,s=-H`
`(n u)^(2)-u^(2)=2gH, (n^(2)-1)u^(2)=2gH`
`therefore H=(u^(2))/(2g)(n^(2)-1)`
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