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A parachutist drops freely from an aerop...

A parachutist drops freely from an aeroplane for 10 seconds before the parachute opens out. Then he descends with a net retardation of `2 "m/sec"^2`. His velocity when he reaches the ground is 8 m/sec. Find the height at which he gets out of the aeroplane ?

Text Solution

Verified by Experts

Distance he falls before the parachute opens is `(1)/(2)gxx100=490m`
Then his velocity = `g t=98.0m//s=u`
Velocity on reaching ground = `8=vartheta` retardation = 2
`vartheta^(2)-u^(2)=2as`
`8^(2)-(98)^(2)=2xx(-2)SthereforeS=(106xx90)/(4)=2385m`
Total distance = `2385+490`
= `2875m` = height of aeroplane
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