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The accelearation due to gravity of t...

The accelearation due to gravity of the earth's surface at the poles is a g and angular velocity of the earth about the axis passing through the pole is `omega`. An object is weight at the equator and at a height h above the poles by using a spring balance. If the weights are found to be same , them h is : `(h lt lt R`, where R is the radius of the earth ).

A

`(omega^(2) R^(2))/(g)`

B

`(omega^(2) R^(2))/(2g)`

C

`(2omega^(2) R^(2))/(g)`

D

`(sqrt(Rg))/(omega)`

Text Solution

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The correct Answer is:
B
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