Home
Class 11
PHYSICS
The mass of the earth is 6xx10^(24) kg a...

The mass of the earth is `6xx10^(24)` kg and that of the moon is `7.4xx10^(22) kg`. The potential energy of the system is `-7.79xx10^(28)J`. The mean distance between the earth and moon is
(G`=6.67xx10^(-11) Nm^(2)kg^(-2)`)

A

`3.80 xx 10^(8) m`

B

`3.37 xx 10^(6) m`

C

`7.60 xx 10^(4) m`

D

`1.90 xx 10^(2) m`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The mass of the earth is 6 × 10^(24) kg and that of the moon is 7.4 xx 10^(22) kg. If the distance between the earth and the moon is 3.84xx10^(5) km, calculate the force exerted by the earth on the moon. (Take G = 6.7 xx 10^(–11) N m^(2) kg^(-2) )

Find the distance of a point from the earth's centre where the resultant gravitational field due to the earth and the moon is zero The mass of the earth is 6.0 xx 10^(24)kg and that of the moon is 7.4 xx 10^(22)kg The distance between the earth and the moon is 4.0 xx 10^(5)km .

Find the distance of a point from the earth's centre where the resultant gravitational field due to the earth and the moon is zero. The mass of the earth is 6.0xx10^24 kg and that of the moon is 7.4x10^22 kg. The distance between the earth and the moon is 4.0xx10^5km .

Calculate the mass of sum if the mean radius of the earth's orbit is 1.5xx10^(8)km and G=6.67xx10^(-11)Nxxm^(2)//kg^(2)

Calculat the binding energy of the - sum system . Mass of the earth =6xx 10 ^(24) kg , mass of the sun = 2 xx 10^(30) kg, distance between the earth and the sun = 1.5 xx 10^(11) and gravitational constant = 6.6 xx 10 ^(-11) N m^(2) kg^(2)

Mass of moon is 7.349 xx 10^(22) kg and its radius is 1.738 xx 10^(6) m . Calculate its mean density and acceleration due to gravity on its surface. Given G = 6668 xx 10^(-11) Nm^(2) kg ^(-2) .

You are given the following data :g=9.81ms^(-2) , radius of earth =6.37xx10^(6)m the distance of the Moon from the earth =3.84xx10^(8) m and the time period of the Moon's revolution =27.3days . Obtain the mass of the earth in two different ways. G=6.67xx10^(-11)Nm^(2)kg^(-2) .

You are given the following data :g=9.81ms^(-2) , radius of earth =6.37xx10^(6)m the distance the Moon from the earth =3.84xx10^(8) m and the time period of the Moon's revolution =27.3days . Obtain the mass of the earth in two different ways. G=6.67xx10^(-11)Nm^(2)kg^(2) .

The force with which the erth attracts an object is called the weight of the object. Calculate the weight of the moon from the following data: The universal constant of gravitastion G=6.67xx10^-11 N-m^2/kg^2 mass of the moon =7.36xx10^22 kg, mass of the earth =6xx10^24 kg and the distasnce between the earth and the moon=3.8xx10^5 km.

The mass of planet Jupiter is 1.9xx10^(7)kg and that of the Sun is 1.99xx10^(30)kg . The mean distance of Jupiter from the Sun is 7.8xx10^(11) m. Calculate the gravitational force which Sun exerts on Jupiter. Assuming that Jupiter moves in circular orbit around the Sun, also calculate the speed of Jupiter G=6.67xx10^(-11)Nm^(2)kg^(-2) .