Home
Class 11
PHYSICS
A body starts from rest from a point hav...

A body starts from rest from a point having distance `R_0` from the centre of the earth. The velocity acquired by the body when it reaches the surface of the earth will be:
(R represents radius of the earth).

A

`sqrt((GMR_(0))/(R+R_(0)))`

B

`sqrt((GMR)/(R+R_(0)))`

C

`sqrt((2GMR_(0))/(R(R+R_(0))))`

D

`sqrt((2GMR)/(R+R_(0)))`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

A body at rest starts from a point at a distance r (gtR) from the centre of the Earth. If M and R stand for the speed of the body when it reaches the Earth surface is

A body starts from rest from a point distant r_(0) from the centre of the earth. It reaches the surface of the earth whose radius is R . The velocity acquired by the body is

A body starts from rest from a point distant r_(0) from the centre of the earth. It reaches the surface of the earth whose radius is R . The velocity acquired by the body is

The escape velocity from the surface of the earth is (where R_(E) is the radius of the earth )

A body is released from a point of distance R' from the centre of earth. Its velocity at the time of striking the earth will be (R’gtR_(e))

If acceleration due to gravity at distance d [ < R ] from the centre of earth is beta , then its value at distance d above the surface of earth will be [ where R is radius of earth ]

The distances from the centre of the earth, where the weight of a body is zero and one-fourth that of the weight of the body on the surface of the earth are (assume R is the radius of the earth)

The escape velocity of a body from the surface of the earth is equal to

A body projected from the surface of the earth attains a height equal to the radius of the earth. The velocity with which the body was projected is

Gravitational potential at a height R from the surface of the earth will be [Take M = mass of the earth, R = radius of the earth]