A particle of mass `m` and charge `q` is projected into a region having a perpendicular magnetic, field `B`. Find the angle of deviation of the particle as it comes out of the magnetic field if the, width of the region is `b`, which is very slightly less than `(mv)/(2Bq)`

Explanation

The radius of path r `=(mv)/(qB)`
For `dger`, we have `sintheta=d/r`
`d=((mv)/(2qB))ltr,sintheta=d/r=((mv)/(2qB))/((mv)/(qB))=1/2` or `theta/6` radian