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A particle of specific charge `alpha` starts moving from (0,0,0) under the action of electric field `E = ehati` and magnetic field `vecB = B_(0)hatk`. Its velocity at (x, 0, 0) is `4hati + 3hatj`. Find the value of x

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To solve the problem, we need to analyze the motion of a charged particle under the influence of electric and magnetic fields. The specific charge of the particle is given as `alpha`, and we have the following fields: - Electric field: \( \vec{E} = E \hat{i} \) - Magnetic field: \( \vec{B} = B_0 \hat{k} \) The velocity of the particle at the point \( (x, 0, 0) \) is given as \( \vec{V} = 4 \hat{i} + 3 \hat{j} \). ### Step-by-step Solution: ...
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AAKASH SERIES-MOVING CHARGES AND MAGNETISM-EXERCISE-III
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