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Find : (i) BC...

Find :

(i) BC

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For (a)
`bar(B_(1))=(mu_(0))/(4pi)i/r,barB_(2)=1/2(mu_(0))/2i/r=(mu_(0)i)/(4r)odot`
`barB_(3)=(mu_(0))/(4pi)i/r=(mu_(0)i)/(4pir)odot,barB_(p)=B_(1)+B_(2)+B_(3)`
`barB_(p)=(mu_(0))/(4pi)i/r+(mu_(0)i)/(4r)odot+(mu_(0))/(4pi)i/rodot,barB_(p)=(mu_(0)i)/(4r)odot`
For (b)
`barB_(1)=barB_(3)=0,barB_(2)=1/2(mu_(0)i)/(2r)=(mu_(0)i)/(4r)`
For (c)
`barB_(1)=0,barB_(2)=3/4(mu_(0)i)/(2r)=(3mu_(0)i)/(8r),barB_(3)=(mu_(0)i)/(4pir)odot`
`barB_(p)=3/4(mu_(0)i)/(2r)+(mu_(0)i)/(4pir)odot=(mu_(0))/4i/r(3/2-1/(pi))`
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AAKASH SERIES-MOVING CHARGES AND MAGNETISM-EXERCISE-III
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