A toroid of non ferromagnetic has core of inner radius 25cm and outer radius 26cm. it has 3500 turns & carries a current of 11A, then find the magnetic field at a point
i) In the internal cavity of toroid
ii) At the midpoint of the windings
iii) At a point which is at a distance of 30cm from the centre of toroid

Explanation

To solve the problem, we will calculate the magnetic field at three different points related to a toroid with given parameters. The parameters are as follows:

- Inner radius (r1) = 25 cm = 0.25 m
- Outer radius (r2) = 26 cm = 0.26 m
- Number of turns (N) = 3500
- Current (I) = 11 A

### i) Magnetic Field in the Internal Cavity of the Toroid
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