A galvanometer has resistance 500 ohm. It is shunted so that its sensitivity decreases by 100 times. Find the shunt resistance.

Explanation

To solve the problem, we need to find the shunt resistance (denoted as \( R_s \)) that decreases the sensitivity of a galvanometer by 100 times. Here are the steps to derive the solution:

### Step 1: Understand the problem
A galvanometer has a resistance \( R_g = 500 \, \Omega \). When a shunt resistance \( R_s \) is added in parallel, the sensitivity of the galvanometer decreases by a factor of 100. This means the new equivalent resistance \( R_{eq} \) is given by:
\[ R_{eq} = \frac{R_g \cdot R_s}{R_g + R_s} \]
And it is equal to \( \frac{R_g}{100} \).
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