The resistance of galvanometer is `999 Omega`. A shunt of `1Omega` is connected to it. If the main current is `10^(-2)A`, what is the current flowing through the galvanometer.

Explanation

To solve the problem, we need to find the current flowing through the galvanometer when a shunt is connected in parallel with it. Here’s a step-by-step solution:

### Step 1: Identify the given values
- Resistance of the galvanometer, \( R_g = 999 \, \Omega \)
- Resistance of the shunt, \( R_s = 1 \, \Omega \)
- Main current, \( I = 10^{-2} \, A \)

### Step 2: Calculate the equivalent resistance of the galvanometer and shunt in parallel
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