A maximum current of 0.5 mA can be passed through a galvanometer of resistance `20Omega`. Calculate the resistance to be connected in series to convert it into a voltmeter of range `(0- 5)V`.

Explanation

To solve the problem, we need to determine the resistance that must be connected in series with a galvanometer to convert it into a voltmeter with a range of 0 to 5 volts. Here’s the step-by-step solution:

### Step 1: Understand the given values
- Maximum current through the galvanometer, \( I = 0.5 \, \text{mA} = 0.5 \times 10^{-3} \, \text{A} \)
- Resistance of the galvanometer, \( R_g = 20 \, \Omega \)
- Voltage range of the voltmeter, \( V = 5 \, \text{V} \)

### Step 2: Calculate the maximum voltage across the galvanometer
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