What is the value of the shunt that passes `10%` of the main current through a galvenomenter of `99 Omega`?

Explanation

As shunt is a small resistance S in parallel with a galvanometer (of resistance G) as shown in fig.
`(I-I_(g))S=I_(G)G`
i.e. `S=(I_(G)G)/((I-I_(G)))`
And as here, `G=99Omega` and
`I_(G)=(10/100)I=0.1IS=(0.1Ixx99)/((I-0.1I))=(0.1)/(0.9)xx99=11Omega`