A galvanometer of resistance `95 Omega`, shunted resistance of `5 Omega`, gives a deflection of `50` divisions when joined in series with a resistance of `20 k Omega` and a `2 V` accumulator. What is the current sensitivity of the galvanomter (in div`//mu A`)?

Explanation

In accordance with given problem, the situation is depicted by the circuit diagram in fig.
As here `20 kOmega` is much greater than the resistance of shunted galvanometer ( < 5`Omega` ),
the current in the circuit will be
`I=2/(20xx10^(3))=10^(-4)A=100muA`
and as this current produces deflection of 50 divisions in the galvanometer
`CS=(theta)/I=(50"div")/(100muA)=1/2("div")/(muA)`