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Two parallel long wires carry currents 18A and 3A. When the currents are in the same direction, the magnetic field at a point midway between the wire is `B_(1)`. If the direction of `i_(2)` is reversed, the field becomes `B_(2)`. Then the value of `B_(1)//B_(2)` is

A

`5:7`

B

`7:5`

C

`3:5`

D

`5:3`

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To solve the problem, we need to calculate the magnetic fields \( B_1 \) and \( B_2 \) at a point midway between two parallel wires carrying currents \( I_1 = 18 \, \text{A} \) and \( I_2 = 3 \, \text{A} \). ### Step-by-Step Solution: 1. **Understanding the Magnetic Field due to a Current-Carrying Wire**: The magnetic field \( B \) at a distance \( r \) from a long straight wire carrying current \( I \) is given by the formula: \[ B = \frac{\mu_0}{2 \pi r} I \] where \( \mu_0 \) is the permeability of free space. 2. **Calculating \( B_1 \) when Currents are in the Same Direction**: When both currents are in the same direction, the magnetic fields due to both wires at the midpoint will add up. Therefore, the magnetic field \( B_1 \) at the midpoint is: \[ B_1 = \frac{\mu_0}{2 \pi r} I_1 - \frac{\mu_0}{2 \pi r} I_2 \] Substituting the values: \[ B_1 = \frac{\mu_0}{2 \pi r} (I_1 - I_2) = \frac{\mu_0}{2 \pi r} (18 - 3) = \frac{\mu_0}{2 \pi r} \cdot 15 \] 3. **Calculating \( B_2 \) when Currents are in Opposite Directions**: When the direction of \( I_2 \) is reversed, the magnetic fields will oppose each other. Therefore, the magnetic field \( B_2 \) at the midpoint is: \[ B_2 = \frac{\mu_0}{2 \pi r} (I_1 + I_2) \] Substituting the values: \[ B_2 = \frac{\mu_0}{2 \pi r} (18 + 3) = \frac{\mu_0}{2 \pi r} \cdot 21 \] 4. **Finding the Ratio \( \frac{B_1}{B_2} \)**: Now we can find the ratio of \( B_1 \) to \( B_2 \): \[ \frac{B_1}{B_2} = \frac{\frac{\mu_0}{2 \pi r} \cdot 15}{\frac{\mu_0}{2 \pi r} \cdot 21} \] The \( \frac{\mu_0}{2 \pi r} \) terms cancel out: \[ \frac{B_1}{B_2} = \frac{15}{21} = \frac{5}{7} \] 5. **Conclusion**: Therefore, the value of \( \frac{B_1}{B_2} \) is \( \frac{5}{7} \). ### Final Answer: \[ \frac{B_1}{B_2} = \frac{5}{7} \]
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