The flux of magnetic field through a closed conducting loop of resistance `0.4 Omega` changes with time according to the equation `Phi =0.20 t^(2)+0.40t+0.60` where `t` is time in seconds.Find (i)the induced `emf` at `t=2s`.(ii)the average induced `emf` in `t=0` to `t=5 s`.(iii)charge passed through the loop in `t=0` to `t=5s` (iv)average current.In time interval `t=0` to `t=5 s` (v) heat produced in `t=0` to `t=5s`

Explanation

`phi= 0.2t^(2) + 0.4t + 0.6`
`e= - (d phi)/(dt) rArr e= - 0.4t- 0.4`
when `t= 2s, e= -0.8 - 0.4 = - 1.2V`