A circular coil of 500 turns of wire has an enclosed area of 0.1 `m^(2)` per turn. It is kept perpendicular to a magnetic field of induction 0.2 T and rotated by `180^(@)` about a diameter perpendicular to the field in 0.1 s. How much charge will pass when the coil is connected to a galvanometer with a combined resistance of 50 `Omega`.

Explanation

Charge `= ("charge in flux")/("resistance")`
`q= (phi_(i) - phi_(f))/(R )= (NBA- (-NBA))/(R )= (2NBA)/(R )`
`q= (2 xx 500 xx 0.2 xx 0.1)/(50)= 0.4C`