The self-inductance of a coil having 200 turns is 10 milli henry. Calculate the magnetic flux through the cross-section of the coil corresponding to current of 4 milliampere. Also determine the total flux linked with each turn.

Explanation

Total magnetic flux linked with the coil, `phi= LI= 10^(-2) H xx 4 xx 10^(-3)A`
`phi= 4 xx 10^(-5)Wb`
Magnetic flux through the cross-section `=(phi)/(200) = 2 xx 10^(-7)Wb`