A solenoid is of length 50 cm and has a radius of 2cm. It has 500 turns. Around its central section a coil of 50 turns is wound. Calculate the mutual inductance of the system.

Explanation

`N_(P)= 500, N_(S)= 50`
`A= pi xx 0.02 xx 0.02m^(2)`
`mu_(0) = 4pi xx 10^(-7) Hm^(-1), l= 50cm= 0.5m`
Now, `M= (mu_(0)N_(P)N_(S)A)/(l)`
`=(4pi xx 10^(-7) xx 500 xx 50 xx pi xx (0.02)^(2))/(0.5)H`
`= 789.8 xx 10^(-7)H= 78.98 mu H`