An inductor of 10mH is connected to a 18V battery through a resistor of `10 kOmega` and a switch. After a long time, when the maximum current is set up in the circuit, the battery is disconnected from the circuit. Calculate the current in the circuit after `15mu s`

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Identify the given values
- Inductance \( L = 10 \, \text{mH} = 10 \times 10^{-3} \, \text{H} \)
- Resistance \( R = 10 \, \text{k}\Omega = 10 \times 10^{3} \, \Omega \)
- Voltage \( V = 18 \, \text{V} \)
- Time \( t = 15 \, \mu s = 15 \times 10^{-6} \, s \)

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