Light of wavelength 5000Å is diffracted by a slit. In diffraction pattern fifth minimum is at a distance of 5 mm from central maximum. If the distance between the screen and the slit is im. Find the slit width.

Explanation

To solve the problem, we need to find the slit width \(d\) given the wavelength of light, the distance of the fifth minimum from the central maximum, and the distance between the slit and the screen.

### Step-by-step Solution:

1. **Identify the given values:**
- Wavelength, \(\lambda = 5000 \, \text{Å} = 5000 \times 10^{-10} \, \text{m}\)
- Distance to the screen, \(D = 1 \, \text{m}\)
- Distance of the fifth minimum from the central maximum, \(x_5 = 5 \, \text{mm} = 5 \times 10^{-3} \, \text{m}\)
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