In double slit experiment, a light of wavelength `lamda` = 600nm is used. When a film of material `3.6xx10^(-3)` cm thick was placed over one of the slits, the fringe pattern was displaced by a distance equal to 30 times the distance between two adjacent dark fringes. What is the refractive index of the material?

Explanation

To solve the problem step by step, we will follow the logic outlined in the video transcript:

### Step 1: Convert Wavelength and Thickness to SI Units
Given:
- Wavelength, \( \lambda = 600 \, \text{nm} = 600 \times 10^{-9} \, \text{m} \)
- Thickness of the film, \( t = 3.6 \times 10^{-3} \, \text{cm} = 3.6 \times 10^{-5} \, \text{m} \)

### Step 2: Understand the Displacement of the Fringe Pattern
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