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In the figure shown S(1)O-S(2)O=S(3)O-S(...

In the figure shown `S_(1)O-S_(2)O=S_(3)O-S_(2)O=(lambda)/(4)`, Intensity at O due to any one of the slits is `I_(0)`. What is the intensity due to all the three coherent sources `S_(1), S_(2) and S_(3)` ?

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`5I_0`
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In the arrangement shown in Fig., slits S_(1) and S_(4) are having a variable separation Z. Point O on the screen is at the common perpendicular bisector of S_(1) S_(2) and S_(3) S_(4) . When Z = (lambda D)/(2d) , the intensity measured at O is I_(0) . The intensity at O When Z = (2 lambda D)/(d) is

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In the arrangement shown in Fig., slits S_(1) and S_(4) are having a variable separation Z. Point O on the screen is at the common perpendicular bisector of S_(1) S_(2) and S_(3) S_(4) . If a hole is made at O' on AO' O and the slit S_(4) is closed, then the ratio of the maximum to minimum observed on screen at O , if O' S_(3) is equal to (lambda D)/(4d) , is

In Young's double slit experiment, the slits are horizontal. The intensity at a point P as shown in figure is (3)/(4) I_(0) ,where I_(0) is the maximum intensity. Then the value of theta is, (Given the distance between the two slits S_(1) and S_(2) is 2 lambda )

Na_(2)S_(2)O_(3) is prepared by :

AAKASH SERIES-WAVE OPTICS-PROBLEMS (LEVEL - II)
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