A horizontal beam of vertically polarized light o intensity `43 w//m^2` is sent through two polarizing sheets. The polarizing direction of the first is `60^@` to the vertical, and that of the second is horizontal. What is the intensity of the light transmitted by the pair of sheets?

Explanation

To solve the problem, we will use Malus's Law, which states that when polarized light passes through a polarizing filter, the intensity of the transmitted light is given by:

\[ I' = I \cdot \cos^2(\theta) \]

where \( I \) is the intensity of the incident light, \( I' \) is the intensity of the transmitted light, and \( \theta \) is the angle between the light's polarization direction and the axis of the polarizer.

### Step-by-Step Solution:

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