Consider a ray of light passing through a prism (angle A) in the position of minimum deviation `delta `. Show that the angles of incidence and refraction are given by: `i=(A+delta )/2 and r= (A/2)`.

For refraction through a small angled prism, the angle of minimum deviation

A ray of light passing through a prism having refractive index sqrt2 suffers minimum deviation. It is found that the angle of incidence is double the angle of refraction within the prism. What is the angle of prism?

A ray passes through a prism of angle 60^(@) in minimum deviation position and suffers a deviation of 30^(@) . What is the angle of incidence on the prism

If the refracting angle of a prism is 60^@ and the minimum deviation is 30^@ , then the angle of incidence is

A light ray of angles of incidence 40^(@) emerged from the prism in minimum deviation position. Then what is the angle of incidence on the second surface ?

Two beam of red and violet colors are made to pass separately through a prism (angle of the prism is 60^(@) ). In the position of minimum deviation, the angle of refraction will be

A ray of light passes from vaccum into a medium of refractive index n. If the angle of incidence is twice the angle of refraction, then the angle of incidence is

The angle of incidence for a ray of light at a refracting surface of a prism is 45^(@) . The angle of prism is 60^(@) . If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are :

The graph between angle of deviation (delta) and angle of incidence (i) for a triangular prism is represented by

A ray of light is incident on a 60^(@) prism at the minimum deviation position. The angle of refraction at the first face (i.e. incident face) of the prism is-