Show that deviation produced by a thin prism of prism angle A and refractive index `mu` is given by `delta = (mu -1) A`.

The minimum deviation produced by a glass prism of angle 40^(@) is 36^(@) . The refractive index of the glass will be

Deviation delta produced by a prism of angle A, which is assumed to be small, made of a material of refractive index mu is given by

The angle of minimum deviation produced by a 60^(@) prism is 40^(@) . Calculate the refractive index of the material of the prism.

The angle of minimum deviation produced by an equilateral prism is 46^@ The refractive index of material of the prism.

A prism of apex angle A=60^@ has the refractive index mu=sqrt2. The angle of incidence for minimum deviation is

(a) How does the angle of deviation produced by a prism change with increase in the angle of incidence. Draw a curve showing the variation in the angle of deviation with the angle of incidence at a prism surface. (b) Using the curve in part (a) above, how do you infer that for a given prism, the angle of minimum deviation delta_("min") is unique for a given light.

Find the angle of deviation suffered by the light ray shown in figure. The refractive index mu= 2.0 for the prism material.

The least angle of deviation for a glass prism is equal to its refracting angle. The refractive index of glass is 1.5. Then the angle of the prism is

The least angle of deviation for a glass prism is equal to its refracting angle. The refractive index of glass is 1.5. Then the angle of the prism is

The angle of minimum deviation from a prism is 37^@ . If the angle of prism is 53^@ , find the refractive index of the material of the prism.