Home
Class 12
PHYSICS
For a transistor beta=40 and I(B)=25muA ...

For a transistor `beta`=40 and `I_(B)=25muA` .Find the value of `I_(E)`

Text Solution

AI Generated Solution

To find the emitter current \( I_E \) for the given transistor parameters, we can follow these steps: ### Step 1: Understand the relationship between the currents The relationship between the collector current \( I_C \), base current \( I_B \), and emitter current \( I_E \) is given by the equation: \[ I_E = I_C + I_B \] ...
Promotional Banner

Topper's Solved these Questions

  • SEMICONDUCTOR DEVICES

    AAKASH SERIES|Exercise Exercise (Long answer questions)|6 Videos
  • SEMICONDUCTOR DEVICES

    AAKASH SERIES|Exercise Exercise (Short answer questions)|27 Videos
  • RAY OPTICS

    AAKASH SERIES|Exercise PROBLEMS ( LEVEL-II)|60 Videos
  • UNITS AND MEASUREMENT

    AAKASH SERIES|Exercise PRACTICE EXERCISE|45 Videos

Similar Questions

Explore conceptually related problems

For a transistor I_(e) = 25 mA and I_(b) = 1mA . The value of current gain alpha will be :-

In common - emitter configuration of a transistor, the base current I_(E)=2muA, alpha=0.9 then the value of I_(C) is

In a transistor, the value of alpha=0.9 . Then the value of beta is:

In the given transistor circuit, the base current is 35 muA . The value of R_(alpha) is V_(AB) is assumed to negiligible :-

For a transistor the value of alpha is 0.9 . beta value is

If i=0.25 amp. In fig then value of R is:-

In a common-base configuration of a transistor (Delta i)/(Delta i_(e)) = 0.98 , then current gain in common emitter configuration of transistor will be

In a transistor, the value of beta is 50. Calculate the value of alpha

For a transistor , alpha_(dc) and beta_(dc) are the current ratios, then the value of (beta_(dc) - alpha_(dc))/(alpha_(dc) . beta_(dc))

Two coherent sources of intensity ratio beta^2 interfere. Then, the value of (I_(max)- I_(min))//(I_(max)+I_(min)) is