In a single state transistor amplifier,When the signal changes by 0.02 V,the base current change by 10 `muA` and collector current by 1mA.If collector load `R_(C)=2 kOmega` and `R_(L)=10kOmega` ,Calculate ,(i)Current Gain (ii)Input impedance ,(iii)Effective a.c load (iv)Voltage gain and (v)Power gain.

Explanation

To solve the problem step by step, we will calculate the required parameters one by one.

### Given Data:
- Change in signal voltage, \( \Delta V = 0.02 \, V \)
- Change in base current, \( \Delta I_B = 10 \, \mu A = 10 \times 10^{-6} \, A \)
- Change in collector current, \( \Delta I_C = 1 \, mA = 1 \times 10^{-3} \, A \)
- Collector load, \( R_C = 2 \, k\Omega = 2000 \, \Omega \)
- Load resistance, \( R_L = 10 \, k\Omega = 10000 \, \Omega \)
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