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There are three concentric thin spherica...

There are three concentric thin spherical shells A, B and C of radii R, 2R, and 3R. Shells A and Care given charges q and 2q and shell B is earthed. Then which of the given is correct ?

A

charge on inner surface of shell C is `4/3`q

B

charge on outer surface of shell B is `-4/3` q

C

charge on outer surface of shell C is ` (2)/(3) q`

D

all the above

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The correct Answer is:
To solve the problem, we need to analyze the charges on the three concentric spherical shells A, B, and C, given that shell B is earthed. Here’s a step-by-step solution: ### Step 1: Understand the Setup We have three concentric spherical shells: - Shell A with radius R and charge \( q \) - Shell B with radius \( 2R \) which is earthed (potential = 0) - Shell C with radius \( 3R \) and charge \( 2q \) ### Step 2: Analyze Shell B (Earthed) Since shell B is earthed, the potential on its surface must be zero. This means that the total charge on shell B must balance the charges from shells A and C. ### Step 3: Determine Charge on Shell B Let \( Q' \) be the charge on the outer surface of shell B. The inner surface of shell B will have a charge of \( -q \) (to balance the charge from shell A) and \( -2q \) (to balance the charge from shell C). Therefore, the total charge on the inner surface of shell B is: \[ Q_{inner, B} = -q - 2q = -3q \] Since the total charge on shell B must be zero (as it is earthed), we have: \[ Q' + (-3q) = 0 \implies Q' = 3q \] ### Step 4: Determine Charge on Shell C The charge on the inner surface of shell C must balance the charge on the outer surface of shell B. Since the outer surface of shell B has a charge of \( 3q \), the inner surface of shell C will have a charge of \( +3q \). The total charge on shell C is \( 2q \), so the charge on the outer surface of shell C will be: \[ Q_{outer, C} = 2q - 3q = -q \] ### Step 5: Final Charges on Each Shell - **Shell A**: - Inner surface: \( 0 \) - Outer surface: \( q \) - **Shell B**: - Inner surface: \( -3q \) - Outer surface: \( 3q \) - **Shell C**: - Inner surface: \( +3q \) - Outer surface: \( -q \) ### Conclusion Now we can summarize the charges: 1. Charge on inner surface of shell C: \( +3q \) 2. Charge on outer surface of shell B: \( 3q \) 3. Charge on outer surface of shell C: \( -q \) Since all calculations are consistent with the problem statement, the correct answer is that all the options provided are correct.
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