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Four identical capacitors each rates as ...

Four identical capacitors each rates as `10 mu F - 10V` are supplied to you to obtain capacitor of `10 mu F - 20 V`, we should connect them in

A

two rows each containing 2 condensers

B

four rows each containing 1 condenser

C

one row containing four condensers

D

all the above

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The correct Answer is:
To solve the problem of obtaining a capacitor of 10 µF - 20 V using four identical capacitors rated at 10 µF - 10 V, we need to determine the correct configuration to achieve the desired capacitance and voltage rating. ### Step-by-Step Solution: 1. **Understanding the Capacitor Ratings**: Each capacitor has a capacitance of 10 µF and a voltage rating of 10 V. We want to achieve a total capacitance of 10 µF and a voltage rating of 20 V. 2. **Voltage Requirement**: To achieve a voltage rating of 20 V, we can connect capacitors in series. When capacitors are connected in series, the total voltage rating is the sum of the individual voltage ratings. 3. **Capacitance in Series**: When capacitors are connected in series, the equivalent capacitance (C_eq) is given by the formula: \[ \frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \ldots + \frac{1}{C_n} \] For two capacitors in series, this simplifies to: \[ C_{eq} = \frac{C}{n} \] where n is the number of capacitors in series. 4. **Connecting Two Capacitors in Series**: If we connect two capacitors in series, the equivalent capacitance will be: \[ C_{eq} = \frac{10 \, \mu F}{2} = 5 \, \mu F \] The voltage rating will be: \[ V_{total} = 10 \, V + 10 \, V = 20 \, V \] 5. **Creating Two Sets of Series Capacitors**: Now we can create two sets of these series capacitors. Each set will have an equivalent capacitance of 5 µF and a voltage rating of 20 V. 6. **Connecting the Two Sets in Parallel**: If we connect these two sets of 5 µF capacitors in parallel, the equivalent capacitance will be: \[ C_{eq} = 5 \, \mu F + 5 \, \mu F = 10 \, \mu F \] The voltage rating remains at 20 V. 7. **Final Configuration**: Therefore, the final configuration to achieve a capacitor of 10 µF - 20 V is to connect two rows, each containing two capacitors in series, and then connect these two rows in parallel. ### Conclusion: The correct answer is to connect the capacitors in **two rows, each containing two capacitors in series**.
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AAKASH SERIES-APPENDICES ( REVISION EXERCISE )-REVISION EXERCISE (ELECTRIC POTENTIAL & CAPACITANCE )
  1. Consider the situation shown in the figure. The capacitor A has a char...

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  2. The capacity of each condenser in the following fig. is .C.. Then the ...

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  3. Four identical capacitors each rates as 10 mu F - 10V are supplied to ...

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  4. Consider the situation shown in the figure. The capacitor A has a char...

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  5. If the potential at A is 2000V the potential at B is

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  6. The P.D between the points A and B is

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  7. The Boolean equation for the given circuit is

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  8. Two condensers of capacities 4mF and 6mF are connected to two cells as...

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  9. In the given circuit P.D. between A and B in the steady state is

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  10. In the given circuit in the steady state (C1 = 2 mF and C2 =6mF)

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  11. Calculate the effective resistance between the points A and B in the c...

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  12. The P.D between the points A and B is

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  13. The potential drop across 7muF capacitor is 6V. Then

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  14. If the capacity of each condenser is 10 mu F, the equivalent capacity ...

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  15. If the equivalent capacity between A and B in the circuit is 12 muF, t...

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  16. In the circuit shown in the figure, each capacitor has a capacity of 3...

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  17. The equivalent capacity between the points A and B in the adjoining ci...

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  18. Find the effective capacitance between the terminals a and b shown in ...

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  19. Find the effective capacitance between the terminals a and b shown in ...

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  20. In the figure, potential difference between A & B is

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