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An electron in the beam of a TV picture ...

An electron in the beam of a TV picture tube is accelerated by a potential difference of `2.00 kV`. Then, it passes through region of transverse magnetic field, where it moves in a circular arc with radius `0.180 m`. what is the magnitude of the field?

A

` ( 2mV )/( sqrt(e r))`

B

`sqrt(( 2mv )/(e r ^2))`

C

`sqrt((2mV )/(r ))`

D

`sqrt((2m Vr)/(e ))`

Text Solution

Verified by Experts

The correct Answer is:
B
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