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A proton (mass m) accelerated by a poten...

A proton (mass m) accelerated by a potential difference V flies through a uniform transverse magnetic field B. The field occupies a region of space by width d. If `alpha` be the angle of deviation of proton from initial direction of motion (see figure), the value of sin `alpha` will be

A

`qV sqrt( (pd )/(2m))`

B

`Bd sqrt((q)/( 2mV))`

C

`(B)/(d ) sqrt((q)/(2mV))`

D

`(B )/(2) sqrt((qd)/(mv))`

Text Solution

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The correct Answer is:
B
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