Home
Class 12
PHYSICS
A solenoid of 1000 turns is wound unifor...

A solenoid of 1000 turns is wound uniform on a glass tube of 50cm long and 10 cm in diameter. Find the strength of magnetic field at the centre of solenoid when 0.1 amp current is flowing through it

A

200 amp-turns/meter

B

50 amp

C

10 amp-turns/meter

D

200 amp

Text Solution

AI Generated Solution

The correct Answer is:
To find the strength of the magnetic field at the center of a solenoid, we can use the formula for the magnetic field inside a solenoid: \[ B = \mu_0 \cdot n \cdot I \] where: - \( B \) is the magnetic field strength, - \( \mu_0 \) is the permeability of free space (\( 4\pi \times 10^{-7} \, \text{T m/A} \)), - \( n \) is the number of turns per unit length of the solenoid, - \( I \) is the current flowing through the solenoid. ### Step 1: Calculate the number of turns per unit length (n) Given: - Total number of turns \( N = 1000 \) - Length of the solenoid \( L = 50 \, \text{cm} = 0.5 \, \text{m} \) The number of turns per unit length \( n \) is given by: \[ n = \frac{N}{L} = \frac{1000}{0.5} = 2000 \, \text{turns/m} \] ### Step 2: Substitute values into the magnetic field formula Now we can substitute \( n \) and \( I \) into the magnetic field formula. Given that the current \( I = 0.1 \, \text{A} \): \[ B = \mu_0 \cdot n \cdot I \] Substituting the values: \[ B = (4\pi \times 10^{-7}) \cdot (2000) \cdot (0.1) \] ### Step 3: Calculate B Calculating the above expression: \[ B = (4\pi \times 10^{-7}) \cdot (200) = 800\pi \times 10^{-7} \, \text{T} \] Using \( \pi \approx 3.14 \): \[ B \approx 800 \cdot 3.14 \times 10^{-7} = 2.512 \times 10^{-4} \, \text{T} = 0.0002512 \, \text{T} \] ### Step 4: Calculate the magnetic field strength (H) The magnetic field strength \( H \) is given by: \[ H = \frac{B}{\mu_0} \] Substituting the values: \[ H = \frac{2.512 \times 10^{-4}}{4\pi \times 10^{-7}} \] Calculating \( H \): \[ H = \frac{2.512 \times 10^{-4}}{1.2566 \times 10^{-6}} \approx 200 \, \text{A/m} \] ### Final Answer Thus, the strength of the magnetic field at the center of the solenoid is: \[ H \approx 200 \, \text{A/m} \]

To find the strength of the magnetic field at the center of a solenoid, we can use the formula for the magnetic field inside a solenoid: \[ B = \mu_0 \cdot n \cdot I \] where: - \( B \) is the magnetic field strength, - \( \mu_0 \) is the permeability of free space (\( 4\pi \times 10^{-7} \, \text{T m/A} \)), - \( n \) is the number of turns per unit length of the solenoid, ...
Promotional Banner

Topper's Solved these Questions

  • APPENDICES ( REVISION EXERCISE )

    AAKASH SERIES|Exercise REVISION EXERCISE (MAGNETISM AND MATTER )|52 Videos
  • APPENDICES ( REVISION EXERCISE )

    AAKASH SERIES|Exercise REVISION EXERCISE (CUTTENT ELECTRICITY )|108 Videos
  • ALTERNATING CURRENT

    AAKASH SERIES|Exercise EXERCISE - III|24 Videos
  • APPENDICES (REVISION EXERCISE)

    AAKASH SERIES|Exercise LAW OF MOTION|128 Videos

Similar Questions

Explore conceptually related problems

A long solenoid of 50 cm length having 100 turns carries a current of 2.5A. The magnetic field at centre of solenoid is:

The strength of magnetic field inside a long current-carrying straight solenoid is:

A solenoid 50 cm long has 4 layers of windings of 350 turns each. If the current carried is 6A. Find the magnetic field at the centre of the solenoid

A tightly wound 100 turn coil of radius 10cm is carrying a current of 1A . What is the magnitude of the magnetic field at the centre of the coil?

A 2A current is flowing through a circular coil of radius 10 cm containing 100 turns. Find the magnetic flux density at the centre of the coil.

A tightly-wound, long solenoid having 50 turns cm^(-1) , carris a current of 4.00 A . Find the magnetic intensity H and the magnetic field B at the centre of the solenoid. What will be the values of these quantities if an iron core is inserted in the solenoid and the magnetization I in the core is 4.00 xx 10^6 A m^(-1) ?

A tightly wound 90 turn coil of radius 15 cm has a magnetic field of 4 xx 10^(-4)T at its centre. The current flowing through it is

A solenoid consists of 100 turns of wire and has a length of 10 cm. The magnetic field inside the solenoid when it carries a current of 0.5 A will be :

What is the self inductance of an air core solenoid 50cm long and 2cm radius if it has 500 turns? Find the magnetic flux when a current of 2 amp passes through it

The magnetic field at a point on the axis of a long solenoid having 5 turns per cm length when a current of 0.8 A flows through it is

AAKASH SERIES-APPENDICES ( REVISION EXERCISE )-REVISION EXERCISE (MOVING CHANGES & MEGNETISM)
  1. A closely wound solenoid of 800 turns and area of cross-section 2.5xx1...

    Text Solution

    |

  2. If a solenoid of magnetic moment 0.6JT^(-1) is free to turn about th...

    Text Solution

    |

  3. A solenoid of 1000 turns is wound uniform on a glass tube of 50cm long...

    Text Solution

    |

  4. A solenoid of length 'l' has N turns of wire closely spaced, each turn...

    Text Solution

    |

  5. A closely would solenoid of 2000 turns and area of cross-section 1.6xx...

    Text Solution

    |

  6. A Rowland ring of mean radius 15 cm has 3500 turns of wire wound on a ...

    Text Solution

    |

  7. Wires 1 and 2 carrying currents i1 and i2 respectively are inclined at...

    Text Solution

    |

  8. Currents of 10 A and 2A are passed through two parallel wires A and B ...

    Text Solution

    |

  9. Three long straight and parallel wires carrying currents are arranged ...

    Text Solution

    |

  10. Two parallel horizontal conductors are suspended by two light vertical...

    Text Solution

    |

  11. Along wire carrying a current of 40A as shown in figure. The rectangul...

    Text Solution

    |

  12. Two long parallel wires are at a distance 2d apart. They carry steady ...

    Text Solution

    |

  13. A conducting ring of mass 2kg, radius 0.5m carries a current of 4A. I...

    Text Solution

    |

  14. A wire fo length l is bent in the from of a circular coil of some tur...

    Text Solution

    |

  15. A rectangular coil 6 cm long and 2 cm wide is placed in a magnetic fie...

    Text Solution

    |

  16. A circular coil of 20 turns and radius 10 cm is placed in uniform magn...

    Text Solution

    |

  17. A moving coil galvanometer 'A' has 200 turns and a resistance of 100Om...

    Text Solution

    |

  18. A tangent galvanometer has 66 turns and the diameter of its coil is 22...

    Text Solution

    |

  19. A galvanometer has a resistance of 3663Omega. A shunt S is connected a...

    Text Solution

    |

  20. A galvanometer having a resistance of 50Omega, gives a full scale defl...

    Text Solution

    |