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A drop of liquid of density rho is float...

A drop of liquid of density `rho` is floating half-immersed in a liquid of density `d`. If `sigma` is the surface tension the diameter of the drop of the liquid is

A

`sqrt((sigma)/(g (2 rho -d))`

B

`sqrt(( 2 sigma)/(g ( 2 rho - d))`

C

`sqrt((6 sigma )/( g ( 2 rho -d))`

D

`sqrt((12 sigma)/( g (2 rho - d)))`

Text Solution

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The correct Answer is:
D
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