Show that the trajectory of an object thrown at certain angle with the horizontal is a parabola.

A point P on the trajectory of a projectile projected at angle with theta with horizontal subtrends angles alpha and beta at the point of landing them

The maximum height attained by a projectile when thrown at an angle theta with the horizontal is found to be half the horizontal range. Then theta is equal to

The angle which the velocity vector of a projectile thrown with a velocity v at an. angle theta to the horizontal Will make with the horizontal after time t of its being thrown up is

If two projectile of same mass are thrown at an angle of 50° and 40° with the horizontal with the same speed then, which of the following statement is true?

A projectile thrown with an initial speed u and the angle of projection 15^@ to the horizontal has a range R . If the same projectile is thrown at an angle of 45^@ to the horizontal with speed 2 u , what will be its range ?

A particle is thrown at time t = 0 with a velocity of 10 ms^(-1) at an angle 60^@ with the horizontal from a point on an inclined plane, making an angle of 30^@ with the horizontal. The time when the velocity of the projectile becomes parallel to the incline is

A particle is thrown at time t = 0 with a velocity of 10 ms^(-1) at an angle 60^@ with the horizontal from a point on an inclined plane, making an angle of 30^@ with the horizontal. The time when the velocity of the projectile becomes parallel to the incline is

A particle is thrown at time t = 0 with a velocity of 10 ms^(-1) at an angle 60^@ with the horizontal from a point on an inclined plane, making an angle of 30^@ with the horizontal. The time when the velocity of the projectile becomes parallel to the incline is

What is the angle made by the trajectory of a projectile with horizontal at maximum height ?

A particle is thrown with a speed is at an angle theta with the horizontal. When the particle makes an angle phi with the horizontal, its speed changes to v, then