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A ball is thrown with velocity 8 ms^(-1)...

A ball is thrown with velocity `8 ms^(-1)` making an angle `60^(@)` with the horizontal . Its velocity will be perpendicular to the direction of initial velocity of projection after a time . Then find 't' `(g = 10 ms^(-2))`

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The correct Answer is:
`1.6/(sqrt(3))s`
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