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A linear harmonic oscillator of force co...

A linear harmonic oscillator of force constant `2 xx 10^(6)N//m` and amplitude `0.01 m` has a total mechanical energy of `160 J`. Its

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Maximum elastic P.E =`1/2 KA^2 = 1/2 xx 2 xx 10^6 xx (0.01)^2 = 100 J`
As the oscillator goes from the extreme to mean position, this is converted into K.E.
So, maximum K.E is 100 J. Since total energy is 160 J, maximum P.E is 160J.
From this it is understood that at the mean position potential energy of the simple harmonic oscillator is minimum which need not be zero.
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