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Displacement-time equation of a particle...

Displacement-time equation of a particle execution SHM is x=A sin(`omegat+pi/6)`
Time taken by the particle to go directly from
`x = -A/2 to x = + A/2 is `

Text Solution

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Period of oscillation is `T= (2pi)/(omega)`
Now time taken in going from mean position to `x= (A)/(2)` or from `x= (A)/(2)` to mean position comes out to be `(T)/(12)`. Therefore, the desired time will be :
`t= 2((T)/(12))= (T)/(6)= (pi)/(3omega)`
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