Home
Class 11
PHYSICS
If the length of a simple pendulum is in...

If the length of a simple pendulum is increased by 2%, then the time period

Text Solution

Verified by Experts

Expression for the time period of a simple pendulum `T= 2pisqrt((l)/(g))`
When length changes from `l_(1)` to `l_(2)` time period changes from `T_(1)` to `T_(2)` keeping g constant.
`(T_(2))/(T_(1))= sqrt((l_(2))/(l_(1))):. (T_(2))/(T_(1))= sqrt((121l)/(100l))= (11)/(10)= ((T_(2))/(T_(1))-1)= ((11)/(10)-1)= (1)/(10) implies (DeltaT)/(T)%= (1)/(10)xx100= 10%`
`:.` Increase in time period = 10%
Promotional Banner

Similar Questions

Explore conceptually related problems

If length of a simple pendulum is increased by 69%, then the percentage increase in its time period is

If the length of a simple pendulum is increased to four times the initial length how is the time period affected?

The error in the measurement of the length of a simple pendulum is 0.1% and the error in the time period is 2% . What is the possible percentage of error in the physical quantity having the dimensional formula LT^(-2) ?

If length of simple pendulum is increased by 6% then percentage change in the time-period will be

The length of a simple pendulum is increased by 44%. The percentage increase in its time period will be

The length of a simple pendulum is decreased by 21% . Find the percentage change in its time period.

If the length of a seconds pendulum is decreased by 2% find the gain or loss per day.

If the length of a simple pendulum is doubled then the % change in the time period is :

If the length of a simple pendulum of a clock incrreases by 2% how much loss or gain of second per day will take place ?

If the metal bob of a simple pendulum is replaced by a wooden bob, then its time period will