Home
Class 11
PHYSICS
Two perfect monoatomic gases at absolute...

Two perfect monoatomic gases at absolute temperature `T_(1)` and `T_(2)` are mixed. There is no loss of energy. Find the temperature of the mixture if the number of moles in the gases are` n_(1)` and `n_(2)`.

A

`T= n_(1) T_(1) + n_(2) T_(2)`

B

`T= ( T_1)/( n_1) + (T_2)/( n_2) `

C

`T= ( n_1 T_1 + n_2 T_2)/( n_1 +n_2)`

D

`T= ( n_(1)^(2) T_(1) + n_(2)^(2) T_(2) )/( n_(1)^(2) + n_(2)^(2) )`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

Two perfect gases at absolute temperature T_(1) and T_(2) are mixed. There is no loss of energy. The masses of the molecules are m_(1) and m_(2) . The number of molecules in the gases are n_(1) and n_(2) . The temperature of the mixture is

Three perfect gases at absolute temperature T_(1), T_(2) and T_(3) are mixed. The masses f molecules are m_(1), m_(2) and m_(3) and the number of molecules are n_(1), n_(2) and n_(3) respectively. Assuming no loss of energy, the final temperature of the mixture is

Three perfect gases at absolute temperature T_(1), T_(2) and T_(3) are mixed. The masses f molecules are m_(1), m_(2) and m_(3) and the number of molecules are n_(1), n_(2) and n_(3) respectively. Assuming no loss of energy, the final temperature of the mixture is

Three perfect gases at absolute temperature T_1,T_2, and T_3 are mixed. The masses of molecules are n_1,n_2 and n_3 respectively. Assuming to loss of energy, the final temperature of the mixture is:

Two monoatomic gases are at absolute temperatures 300 K and 350 K respectively. Ratio of average kinetic energy of their molecules is

If 2 mol of an ideal monatomic gas at temperature T_(0) are mixed with 4 mol of another ideal monatoic gas at temperature 2 T_(0) then the temperature of the mixture is

If 2 mol of an ideal monatomic gas at temperature T_(0) are mixed with 4 mol of another ideal monatoic gas at temperature 2 T_(0) then the temperature of the mixture is

Equal volumes of two monoatomic gases, A,B at the same temperature and pressure are mixed.The ratio of specific heats (C_(p)//C_(v)) of the mixture will be

3 mole of O2 mixed with 5 moles of Argon at temperature T. Find total internal energy of system

Two adiabatic containers have volumes V_(1) and V_(2) respectively. The first container has monoatomic gas at pressure p_(1) and temperature T_(1) . The second container has another monoatomic gas at pressure p_(2) and temperature T_(2) . When the two containers are connected by a narrow tube, the final temperature and pressure of the gases in the containers are P and T respectively. Then