A magnet vibrates in a magnetic field of strength `10^(-4)` T. If the moment of the magnet is `10^(-1)A-m^2` and the moment of inertia about the axis of rotation is `10^(-5) kg m^(2)`, then find the time period of oscillation in seconds?

Explanation

To find the time period of oscillation of a magnet in a magnetic field, we can use the formula for the time period \( T \) given by:

\[ T = 2\pi \sqrt{\frac{I}{mB}} \]

where:
- \( I \) is the moment of inertia,
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