In a hydrogen atom, the electron revolves round the nucleus `6.8 xx 10^(15)` times per second in an orbit of radius `0.53Å`. What is equivalent magnetic moment ? (Given that `e=1.6 xx 10^(-19)C`).

Explanation

To find the equivalent magnetic moment of the hydrogen atom, we can follow these steps:

### Step 1: Understand the parameters given
We have:
- Frequency of electron revolution, \( f = 6.8 \times 10^{15} \) revolutions per second.
- Radius of the orbit, \( r = 0.53 \, \text{Å} = 0.53 \times 10^{-10} \, \text{m} \).
- Charge of the electron, \( e = 1.6 \times 10^{-19} \, \text{C} \).

...