A magnet is suspended at an angle ` 60^@` in an external magnetic field of ` 5 xx 10^(-4) T `. What is the work done by the magnetic field in bringing it in its direction ? [ The magnetic moment = `20 A-m^(2)`]

Explanation

To find the work done by the magnetic field in bringing the magnet in its direction, we can follow these steps:

### Step 1: Understand the Formula for Work Done
The work done \( W \) in a magnetic field when a magnetic moment \( m \) is rotated from an angle \( \theta_1 \) to \( \theta_2 \) is given by the formula:
\[ W = -mB \cos(\theta_1) + mB \cos(\theta_2) \]
This can be simplified to:
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