A magnetising field of `1500A m^(-1)` produces flux of `2.4xx 10^(-5)` weber in a iron bar of the cross-sectional area of `0.5cm^(2)`. The permeability of the iron bar is

Explanation

Magnetic induction `, B = (phi)/(A) = (2.4 xx 10^(-5))/(0.2 xx 10^(-4))`
` =1.2 Wb//m^(2)`
i) Permeability , `mu=(B)/(H) = (1.2)/(1600) = 7.5 xx 10^(-4) TA^(-1)m`
ii)As `mu=mu_0(1+ chi_m) ` then
Susceptibility , ` chi_m =(mu)/(mu_0)-1 =(7.5 xx 10^(-4))/( 4 pi xx 10^(-7)) -1`
`=596.1 `