An iron bar of length 10 cm and diameter 2cm is placed in a magnetic field of intensity 1000`Am^(-1)` with its length parallel to the direction of the field. Determine the magnetic moment produced in the bar if permeability of its material is `6.3 xx 10^(-4) TmA^(-1)`.

Explanation

To solve the problem of finding the magnetic moment produced in an iron bar placed in a magnetic field, we can follow these steps:

### Step 1: Identify the given values
- Length of the iron bar, \( l = 10 \, \text{cm} = 0.1 \, \text{m} \)
- Diameter of the iron bar, \( d = 2 \, \text{cm} = 0.02 \, \text{m} \)
- Radius of the iron bar, \( r = \frac{d}{2} = 0.01 \, \text{m} \)
- Magnetic field intensity, \( H = 1000 \, \text{A/m} \)
- Permeability of the material, \( \mu = 6.3 \times 10^{-4} \, \text{Tm/A} \)
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