Describe the principle of working of deflection magnetometer. Explain how the magnetic moments of two short bar magnets can be compared in tan A position by Null method.

The needle of a deflection galvanometer shows a deflection of 60^(@) due to a short bar magnet at a certain distance in tan A position. If the distance is doubled, the deflection is

For a vibration magnetometer, the time period of suspended bar magnet can be reduced by -

The time period of the magnetic in an oscillation pmagnetometer in the earth magnetic field is 2s. A short bar magnet is placed to the north of the magnetometer, at a separation 10cm from the oscillation magnet, with its north pole pointing towards north. The time period beceomes half. Calculate the magnetic moment of this short magnet.

The magnetic field at a distance d from a short bar magnet in longitudinal and transverse positions are in the ratio.

How are the two bar magnets shown alongside stored?

How can a magnet be prepared by the induction method?

Two short magnet having magnetic moment in the ratio 27:8 , when placed on the opposite sides of a deflection magnetometer, produce no deflection. If the distance of the weaker magnet is 0.12m from the centre of deflection magnetometer, the distance of the stronger magnet from the centre is

Magnetic intensity for an axial point due to a short bar magnet of magnetic moment M is given by

The tangents deflection produced in tan A and B positions by a short magnet at equal distances are in the ratio .

A bar magnet of length 5cm, width 3cm and height 2cm takes 5s to complete an oscillation in viberation magnetometer placed in a horizontal magnetic field of 20muT . The mass of this bar magnet is 250g(a). Find the magnetic moment of the magnet. (b) If the magnet is put in the magnetormer with its 0.5cm edge horizontal, what would be the new time period?