At what angle with the magnetic meridian will a magnetic needle rest if it is subjected to a magnetic field of induction`0.6 xx 10^(-4)T` perpendicular to the magnetic meridian? (`B_H=0.2 xx 10^(-4)T`)

Explanation

To solve the problem, we need to find the angle \( \delta \) at which a magnetic needle will rest when subjected to a magnetic field of induction \( B = 0.6 \times 10^{-4} \, \text{T} \) that is perpendicular to the magnetic meridian, while the horizontal component of the magnetic field \( B_H = 0.2 \times 10^{-4} \, \text{T} \).

### Step-by-step Solution:

1. **Identify the Given Values**:
- Total magnetic field induction, \( B = 0.6 \times 10^{-4} \, \text{T} \)
- Horizontal component of the magnetic field, \( B_H = 0.2 \times 10^{-4} \, \text{T} \)

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