A rod of cross sectional area `10cm^(2)` is placed with its length parallel to a magnetic field of intensity 1000 `Am^(-1)`. The flux through the rod is `10^(4) Wb`. Find the permeability of the material of the rod.

Explanation

To find the permeability of the material of the rod, we can follow these steps:

### Step 1: Identify the given values
- Cross-sectional area \( A = 10 \, \text{cm}^2 \)
- Magnetic field intensity \( H = 1000 \, \text{A/m} \)
- Magnetic flux \( \Phi = 10^4 \, \text{Wb} \)

### Step 2: Convert the area from cm² to m²
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